One word:



micromanaged

[quote=charlie2]Would appreciate any thoughts, opinions on program at Chase. How is payout? How did you do in first year? How is platform?[/quote]

highly integrated and VERY retail- bank manager wanted FA's to work the ATM machine-

if you can land in the right branch w/ good bankers and good clients, you'll learn a lot in a hurry and make some money, top end of median $120,000-

top end of median $120,000-

That's an intersting term, what do you mean?

[quote=Farmboy]

top end of median $120,000-

That's an intersting term, what do you mean?

[/quote]

median in my state while at Chase was b/t $75k and $120k

[quote=TexasRep][quote=Farmboy]

top end of median $120,000-

That's an intersting term, what do you mean?

[/quote]

median in my state while at Chase was b/t $75k and $120k

[/quote]

Median is a number, not a range of numbers.

[quote=knucklehead][quote=TexasRep][quote=Farmboy]

top end of median $120,000-

That's an intersting term, what do you mean?

[/quote]

median in my state while at Chase was b/t $75k and $120k

[/quote]

Median is a number, not a range of numbers.

[/quote]

oh yeah...i meant to say..

eleventy kabillion!!

(that's so much easier than trying to actually engage w/ some of you guys)

[quote=TexasRep][quote=knucklehead][quote=TexasRep][quote=Farmboy]

top end of median $120,000-

That's an intersting term, what do you mean?

[/quote]

median in my state while at Chase was b/t $75k and $120k

[/quote]

Median is a number, not a range of numbers.

[/quote]

oh yeah...i meant to say..

eleventy kabillion!!

(that's so much easier than trying to actually engage w/ some of you guys)

[/quote]

You can't engage if you don't use the same word definitions as EVERYBODY else.

can't i?

I bet that most people got when i said "top end" i was speaking of a median range-

the rest? idiots or dirty little fight-pickers.

[quote=TexasRep]

can't i?

I bet that most people got when i said "top end" i was speaking of a median range-

the rest? idiots or dirty little fight-pickers.

[/quote]

no, you can't. there is no such thing as a "median range."

[quote=knucklehead][quote=TexasRep]

can't i?

I bet that most people got when i said "top end" i was speaking of a median range-

the rest? idiots or dirty little fight-pickers.

[/quote]

no, you can't. there is no such thing as a "median range."

[/quote]

just as i figured....idiot.

I do know the top rep did 4.2 million last year, there is an article about her in bank investment magazine (she actually was with Bank One now Chase).

[quote=TexasRep][quote=knucklehead][quote=TexasRep]

can't i?

I bet that most people got when i said "top end" i was speaking of a median range-

the rest? idiots or dirty little fight-pickers.

[/quote]

no, you can't. there is no such thing as a "median range."

[/quote]

just as i figured....idiot.

[/quote]

If I were you, I'd try to distract everyone from the fact that you don't know what median means, too. A tactic that was perfected by Hillary Clinton.

or you could do something really useful and look it up instead of simply demonstating what an ass you are--
http://en.wikipedia.org/wiki/Median

There may be more than one median: for example if there are an even number of cases, and the two middle values are different, then there is no unique middle value. Notice, however, that at least half the numbers in the list are less than or equal to either of the two middle values, and at least half are greater than or equal to either of the two values, and the same is true of any number between the two middle values. Thus either of the two middle values and all numbers between them are medians in that case.

When the median is used as a location parameter in descriptive statistics, there are several choices for a measure of variability: the range, the interquartile range, and the absolute deviation. Since the median is the same as the second quartile, its calculation is illustrated in the article on quartiles. To obtain the median of an even number of numbers, find the average of the two middle terms.

For any probability distribution on the real line with cumulative distribution function F, regardless of whether it is any kind of continuous probability distribution, in particular an absolutely continuous distribution (and therefore has a probability density function), or a discrete probability distribution, a median m satisfies the equality

OR

in which a Riemann-Stieltjes integral is used. For an absolutely continuous probability distribution with probability density function f, we have

The median is primarily used for skewed distributions, which it represents more accurately than the arithmetic mean. Consider the set { 1, 2, 2, 2, 3, 9 }. The median is 2 in this case, as is the mode, and it might be seen as a better indication of central tendency than the arithmetic mean of 3.166….

Calculation of medians is a popular technique in summary statistics and summarizing statistical data, since it is simple to understand and easy to calculate, while also giving a measure that is more robust in the presence of outlier values than is the mean.

Thanks for proving yourself stupid.

[quote=knucklehead]Thanks for proving yourself stupid. [/quote]

figures....can't read well either, huh?

[quote=TexasRep]

[quote=knucklehead]Thanks for proving yourself stupid. [/quote]

figures....can't read well either, huh?

[/quote]

Young lady, I'll give you the last word, since you're so desperate to have it.

nawh...you go ahead.

[quote=bankrep1]I do know the top rep did 4.2 million last year, there is an article about her in bank investment magazine (she actually was with Bank One now Chase).[/quote]

i worked with a guy doing over $1.5 mil- International Biz